A) 4
B) 3
C) 2
D) 1
Correct Answer: C
Solution :
Intensity at the centre of bright fringe, \[{{I}_{0}}=I+I+2\sqrt{I\,I}\cos 0{}^\circ \] \[{{I}_{0}}=2I+2I\] \[{{I}_{0}}=4I\] Intensity at a point distant\[\beta /4\](with a phase difference\[=2\pi /4=\pi /2)\]is \[I=I+I+2\sqrt{I\,I}\cos \frac{\pi }{2}\] \[I=2I+2\sqrt{I\,I}\times 0\] \[I=2I\] \[\therefore \] \[\frac{{{I}_{0}}}{I}=\frac{4I}{2I}=2\]You need to login to perform this action.
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