A) 2-methylbut-2-enoic acid
B) 3-methylbut-2-enoic acid
C) 3-methylbut-3-enoic acid
D) 2-methylbut-3-enoic acid
Correct Answer: B
Solution :
\[\underset{3-methylbut-2-enoic\text{ }acid}{\mathop{{{H}_{3}}\overset{4}{\mathop{C}}\,-\overset{\begin{smallmatrix} C{{H}_{3}} \\ 4| \end{smallmatrix}}{\mathop{C}}\,=\overset{\begin{smallmatrix} H \\ 2| \end{smallmatrix}}{\mathop{C}}\,-\overset{1}{\mathop{C}}\,OOH}}\,\] [\[\because \]Order of preference: COOH > (=) > alkyl group.]You need to login to perform this action.
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