A) formaldehyde
B) ethanal
C) glyoxal
D) propanaldehyde
Correct Answer: C
Solution :
\[C{{H}_{2}}=CH-CH=CH-C{{H}_{3}}\xrightarrow[{}]{{{O}_{3}}}\] \[\xrightarrow[{}]{Zn/{{H}_{2}}O}\underset{formaldehyde}{\mathop{HCHO}}\,+\underset{glyoxal}{\mathop{\underset{\begin{smallmatrix} | \\ CHO \end{smallmatrix}}{\mathop{CHO}}\,}}\,+\underset{acetaldehyde}{\mathop{C{{H}_{3}}CHO}}\,\]You need to login to perform this action.
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