Uttarakhand PMT Uttarakhand PMT Solved Paper-2009

  • question_answer
    The molarity of a solution containing 5.0 g of \[NaOH\]in 250 mL solution is

    A)  0.1            

    B)  0.5

    C)  1.0            

    D)  2.0

    Correct Answer: B

    Solution :

     Molanty\[=\frac{number\text{ }of\text{ }moles\text{ }of\text{ }solute}{volume\text{ }of\text{ }solution}\] \[=\frac{5\times 1000}{40\times 250}\][\[\because \]moles of\[NaOH=\frac{5}{40}\]] \[=0.5\,M\]


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