A) 0.064
B) 0.8
C) 0.64
D) 0.32
Correct Answer: C
Solution :
According to Hardy-Weinberg law, the allelic frequency \[{{\left( A+a \right)}^{2}}=1\] or \[A+a=1\] and for genetic frequency \[{{A}^{2}}+2Aa+{{a}^{2}}=1\] where A = The frequency of dominant allele and a = The frequency of recessive allele In the question, \[a=0.2\] So, \[A+0.2=1\] \[A=0.8\] So, the genotypic frequency of homozygous dominant \[AA=0.8\times 0.8=0.64.\]You need to login to perform this action.
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