A) 0.1 m
B) 0.2 m
C) 0.3m
D) 0.4m
Correct Answer: A
Solution :
By law of conservation of energy, we have Loss in gravitational potential energy = gain in elastic potential energy \[\Rightarrow \] \[mg(h+x)=-\text{ }k{{x}^{2}}\] \[2\times 9.8(0.4+x)=\frac{1}{2}\times 1960\times {{x}^{2}}\] \[(0.4+x)=\frac{980{{x}^{2}}}{2\times 9.8}\] or \[50{{x}^{2}}-x-0.4=0\] Solving we get, \[x=0.1m\]
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