A) 10.3m
B) 41.2m
C) 20.4m
D) 24.9m
Correct Answer: C
Solution :
Velocity of the stone at any instant \[v=r\omega =r2\pi n\] \[=80\times {{10}^{-2}}\times 2\times 3.14\times \frac{240}{60}\] \[=20\text{ }m/s\] So, maximum height attained by the stone \[=\frac{{{v}^{2}}}{2g}\] \[=\frac{{{(20)}^{2}}}{2\times 9.8}\simeq 20.4\,m\]You need to login to perform this action.
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