Uttarakhand PMT Uttarakhand PMT Solved Paper-2010

  • question_answer
    The ratio of the adiabatic bulk modulus to the isothermal bulk modulus of a perfect gas is equal to (symbols have their usual meanings)

    A) \[{{C}_{p}}-{{C}_{v}}\]

    B) \[\frac{{{C}_{p}}}{{{C}_{v}}}\]

    C) \[\frac{{{C}_{v}}}{{{C}_{p}}}\]

    D) \[\sqrt{\frac{{{C}_{p}}}{{{C}_{v}}}}\]

    Correct Answer: B

    Solution :

     Adiabatic bulk modulus\[={{B}_{adia}}=\gamma p\] Isothermal bulk modulus\[={{B}_{iso}}=p\] \[\Rightarrow \] \[\frac{{{B}_{adia}}}{{{B}_{iso}}}=\gamma =\frac{{{C}_{p}}}{{{C}_{V}}}\]


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