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Uttarakhand PMT Uttarakhand PMT Solved Paper-2011

  • question_answer
    The gas in a vessel is subjected to a pressure of 20 atm at a temperature\[27{}^\circ C\]. The pressure of the gas in a vessel after one-half of the gas is released from the vessel and the temperature of the remainder is raised by\[50{}^\circ C\] is

    A)  8.5 atm         

    B)  10.8 atm

    C)  11.7 atm        

    D)  17 atm

    Correct Answer: C

    Solution :

     Apply \[pV=\mu RT=\frac{m}{M}RT\] \[20\times V=\frac{m}{M}\times R\times 300\]          ...(i) \[p\times V=\frac{\left( \frac{m}{2} \right)}{M}R\times 350\]         ...(ii) From Eqs. (i) and (ii), we get \[p=\frac{140}{12}\approx 11.7\,atm\]


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