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Uttarakhand PMT Uttarakhand PMT Solved Paper-2011

  • question_answer
    The moment of magnet is\[0.1\text{ }A-{{m}^{2}}\]and the force acting on each pole in a uniform magnetic field of 0.36 oersted is\[1.44\times {{10}^{-4}}\] N. The distance between the poles of magnet is

    A)  2.5 cm          

    B)  5.0 cm

    C)  1.25cm         

    D)  1.17cm

    Correct Answer: A

    Solution :

     Here,     \[M=0.1\text{ }A{{m}^{2}},\] \[B=0.36\text{ }oersted\] \[=0.36\times {{10}^{-4}}J\] and      \[F=1.44\times {{10}^{-4}}N\] As  \[F=mB\] \[\therefore \] \[2l=\frac{M}{m}=\frac{0.1}{4}m=2.5\,cm\]


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