A) 300 kg wt
B) 400 kg wt
C) 500 kg wt
D) 600 kg wt
Correct Answer: D
Solution :
\[F={{f}_{k}}=ma\] \[F={{f}_{k}}+ma\] \[F=\mu mg+ma\] \[f=m(\mu g+a)\] \[\therefore \] \[F=(500+1500)\text{ }(0.2\times 10+1)\] \[F=6000\text{ }N\] \[F=600\text{ }kg-wt\]You need to login to perform this action.
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