A) \[2l\]
B) \[4l\]
C) \[4lx\]
D) \[\frac{41}{x}\]
Correct Answer: B
Solution :
Time period of simple pendulum \[T=2\pi \sqrt{\frac{l}{g}}\] Time period does not depend on density of bob. \[T\propto \sqrt{l}\] (\[l=\]length of pendulum) \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{l}_{1}}}{{{l}_{2}}}}\] \[\frac{T}{2T}=\sqrt{\frac{l}{{{l}_{2}}}}\] Hence, \[{{l}_{2}}=4l\] Hence, new length is\[4l.\]You need to login to perform this action.
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