A) 8.5 atm
B) 10.8 atm
C) 11.7 atm
D) 17 atm
Correct Answer: C
Solution :
Apply \[pV=\mu RT=\frac{m}{M}RT\] \[20\times V=\frac{m}{M}\times R\times 300\] ...(i) \[p\times V=\frac{\left( \frac{m}{2} \right)}{M}R\times 350\] ...(ii) From Eqs. (i) and (ii), we get \[p=\frac{140}{12}\approx 11.7\,atm\]You need to login to perform this action.
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