A) positron
B) one neutron
C) proton
D) alpha particle
Correct Answer: B
Solution :
\[_{52}T{{e}^{130}}{{+}_{1}}{{H}^{2}}{{\xrightarrow[{}]{{}}}_{53}}{{I}^{131}}+\underset{neutron}{\mathop{_{0}{{n}^{1}}}}\,\]You need to login to perform this action.
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