A) \[2A\]
B) A
C) \[\frac{A}{2}\]
D) \[\frac{A}{4}\]
Correct Answer: C
Solution :
\[I\propto {{A}^{2}}\] Also, \[I\propto \frac{1}{{{r}^{2}}}\] (inverse square law) \[A\propto \frac{1}{r}\] \[\therefore \] \[A=\frac{A}{2}\]You need to login to perform this action.
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