A) 2
B) \[{{10}^{-2}}\]
C) 1
D) 100
Correct Answer: B
Solution :
\[Zn+C{{u}^{2+}}\xrightarrow[{}]{{}}Z{{n}^{2+}}+Cu\] \[{{E}_{cell}}-E_{cell}^{o}=-\frac{0.0591}{2}\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}\] \[0.0591=-\frac{0.0591}{2}\log \frac{{{C}_{1}}}{{{C}_{2}}}\] \[\log \frac{{{C}_{1}}}{{{C}_{2}}}=-2\] \[\frac{{{C}_{1}}}{{{C}_{2}}}=Anti\log \overline{2}={{10}^{-2}}\]You need to login to perform this action.
You will be redirected in
3 sec