A) 2.54
B) 1.17
C) 2.99
D) 29.9
Correct Answer: C
Solution :
\[150\text{ }mL\text{ }{{C}_{2}}{{H}_{5}}OH=150\times 0.78\text{ }g\] \[=117.0g=\frac{117}{46}mol\] Water\[=1000-150=850\text{ }g\] Molality\[=\frac{117}{46}\times \frac{1}{850}\times 1000=2.99\]
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