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Uttarakhand PMT Uttarakhand PMT Solved Paper-2011

  • question_answer
    The rate constant for the reaction, \[2{{N}_{2}}{{O}_{5}}\xrightarrow[{}]{{}}4N{{O}_{2}}+{{O}_{2}}\] is\[3.0\times {{10}^{-5}}{{s}^{-1}}\]. If the rate is\[2.40\times {{10}^{-5}}\]then the concentration of\[{{N}_{2}}{{O}_{5}}\](in mol/L) is

    A)  1.4               

    B)  1.2

    C)  0.04              

    D)  0.8

    Correct Answer: D

    Solution :

     For a reaction, rate = k [reactants] [Reactants] \[=\frac{rate}{k}\] \[=\frac{2.40\times {{10}^{-5}}}{3.0\times {{10}^{-5}}}=0.8\,mol/L\]


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