A) 50 kJ
B) 100 kJ
C) 25 kJ
D) \[-25\text{ }kJ\]
Correct Answer: C
Solution :
Work done by the engine is given by \[\frac{W}{Q}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\frac{W}{50\times {{10}^{3}}}=1-\frac{600}{1200}\] \[\frac{W}{50\times {{10}^{3}}}=1-\frac{1}{2}\] \[\Rightarrow \] \[W=25\times {{10}^{3}}J=25\,kJ\]You need to login to perform this action.
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