A) 40 cm
B) 20 cm
C) 10 cm
D) 30 cm
Correct Answer: B
Solution :
Suppose, potential at point P is zero. \[{{V}_{1}}={{V}_{2}}\] \[K\times \frac{4\times {{10}^{-8}}}{{{r}_{1}}}=K\times \frac{6\times {{10}^{-8}}}{{{r}_{2}}}\] \[\frac{4\times {{10}^{-8}}}{x}=\frac{6\times {{10}^{-8}}}{(50-x)}\] \[4(50-x)=6x\] \[200-4x=6x\] \[\Rightarrow \] \[10x=200\] \[x=20\text{ }cm\]You need to login to perform this action.
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