A) decreases
B) increases
C) remains the same
D) sometimes increases or decreases .
Correct Answer: A
Solution :
Here, \[{{v}_{s}}=0\] and \[{{v}_{L}}\] is negative where \[{{v}_{s}}\] is velocity of source and \[{{v}_{L}}\] is velocity of listener (aeroplane) If apparent frequency is v and v is actual frequency, then \[v=\frac{v-(-{{v}_{L}})}{v}v\] \[=\frac{v+{{v}_{L}}}{v}v\] i.e., \[v>v\] So, apparent frequency will increase, it means apparent wavelength will decrease.You need to login to perform this action.
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