A) zero
B) \[\frac{1}{4}\]B0 qv
C) \[\frac{1}{2}q{{B}_{0}}v\]
D) \[q{{B}_{0}}v\]
Correct Answer: C
Solution :
Magnetic field induction at \[P=0,\]magnetic field induction at\[O={{B}_{0}}\]. Average magnetic field induction from P to \[O=\frac{0+{{B}_{0}}}{2}=\frac{{{B}_{0}}}{2}\] Force experienced by a charge while moving alotig the asds of wire, l?-, from P to O will be \[=\frac{{{B}_{0}}}{2}\times q\times v\] \[=\frac{1}{2}{{B}_{0}}qv\]You need to login to perform this action.
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