A) \[12\Omega \]
B) \[6\Omega \]
C) \[3\Omega \]
D) \[\frac{1}{3}\Omega \]
Correct Answer: C
Solution :
The equivalent circuit is given by \[4\Omega \] and \[2\Omega \] resistances are in series on both sides \[\therefore \] \[4\Omega +2\Omega =6\Omega \] Then \[6\Omega \] and \[6\Omega \]resistances are in parallel on both sides \[\frac{1}{R}=\frac{1}{6}+\frac{1}{6}=\frac{2}{6}\] \[=\frac{1}{3}\] \[R=3\Omega \]You need to login to perform this action.
You will be redirected in
3 sec