A) \[0\]
B) \[1.87\]
C) \[5.92\]
D) \[2\]
Correct Answer: A
Solution :
Magnetic moment of \[Z{{n}^{2+}}\] \[\mu \]effective \[=\sqrt{n(n+2)}\] BM where, n = Number of unpaired electrons \[_{30}Zn=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{10}},4{{s}^{2}}\] \[Z{{n}^{2+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}\] So, magnetic moment of \[Z{{n}^{2+}}=\] zeroYou need to login to perform this action.
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