A) 420 nm
B) 450 nm
C) 630 nm
D) 1260 nm
Correct Answer: B
Solution :
\[{{n}_{1}}{{\lambda }_{1}}={{n}_{2}}{{\lambda }_{2}}\] \[\therefore \] \[{{n}_{1}}\times 420={{n}_{2}}\times 630\] or \[2{{n}_{1}}=3{{n}_{2}}\] If \[{{n}_{2}}=2,\] then \[{{n}_{1}}=3\] Therefore, thickness of soap solution is given by \[{{\mu }_{1}}t={{n}_{1}}\frac{{{\lambda }_{1}}}{2}\] or \[t=\frac{3\times 420}{1.4\times 2}=450nm\]You need to login to perform this action.
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