A) [1, 12]
B) [12, 34]
C) [35, 50]
D) [-12, 12]
Correct Answer: B
Solution :
Given, \[f(x)={{x}^{3}}+3x-2\] On differentiating w.r.t. x, we get \[f(x)=3{{x}^{2}}+3\] Put \[f(x)=0\Rightarrow 3{{x}^{2}}+3=0\] \[\Rightarrow \] \[{{x}^{2}}=-1\] \[\therefore \] \[f(x)\]is either increasing or decreasing. At \[x=2,\,f(2)={{2}^{3}}+3(2)-2=12\] At \[x=3,f(3)={{3}^{3}}+3(3)-2=34\] \[\therefore \]\[f(x)\in [12,34]\].You need to login to perform this action.
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