A) 0
B) \[c\]
C) \[a\]
D) \[{{c}^{4}}\]
Correct Answer: A
Solution :
Given, \[{{x}^{2}}{{y}^{2}}={{c}^{4}}\] \[\Rightarrow \] \[{{y}^{2}}({{a}^{2}}-{{v}^{2}})={{c}^{4}}\] \[\Rightarrow \] \[{{y}^{2}}-{{a}^{2}}{{y}^{2}}+{{c}^{4}}=0\] Let \[{{y}_{1}},{{y}_{2}},{{y}_{3}}\] and \[{{y}_{4}}\] are the roots. \[\therefore \] \[{{y}_{1}}+{{y}_{2}}+{{y}_{3}}+{{y}_{4}}=0\]You need to login to perform this action.
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