A) \[{{107}^{o}}\]
B) \[{{109}^{o}}28\]
C) \[\underline{X}\]
D) \[\underline{X}\]
Correct Answer: D
Solution :
Buffer capacity, \[\beta =\frac{d{{C}_{HA}}}{{{d}_{pH}}}\], where, \[d{{C}_{HA}}\] = no. of moles of acid added per litre \[{{d}_{pH}}\] = change in pH \[d{{C}_{HA}}=\frac{moles\,\,of\,\,acertic\,\,acid}{volume}\] \[=\frac{0.12/60}{250/1000}=\frac{1}{125}\] \[\therefore \] \[\beta =\frac{1/125}{0.02}=\frac{1}{2.5}=0.4\]You need to login to perform this action.
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