(I) \[{{103}^{o}}\] |
(II) \[{{107}^{o}}\] |
(III) \[{{109}^{o}}28\] |
A)
\[\underline{X}\] \[\underline{X}\] \[p\pi .d\pi \] [a] \[Xe{{O}_{3}}\] \[Xe{{O}_{4}}\] \[Xe{{O}_{4}}\]
B)
\[\underline{X}\] \[\underline{X}\] \[p\pi .d\pi \] [b] \[\Delta {{H}_{f}}(H)=218kJ/mol\] \[H-H\] \[52.15\]
C)
\[\underline{X}\] \[\underline{X}\] \[p\pi .d\pi \] [c] \[911\] \[104\] \[52153\]
D)
\[\underline{X}\] \[\underline{X}\] \[p\pi .d\pi \] [d] \[Alkyne\xrightarrow[Lindlars\,\,catalyst]{{{H}_{2}}}A\xrightarrow{Ozonolysis}\underset{only}{\mathop{B}}\,\] \[\xleftarrow[\Pr ocess]{Wac\ker }C{{H}_{2}}=C{{H}_{2}}\] \[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\]
Correct Answer: C
Solution :
I. II. \[C{{H}_{3}}COOH\xrightarrow{{}}6HI\xrightarrow{\operatorname{Re}d\,P}C{{H}_{3}}C{{H}_{3}}+3{{I}_{2}}\] \[+2{{H}_{2}}O\] III.You need to login to perform this action.
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