A) \[Xe{{O}_{4}}\]
B) \[3:5\]
C) \[\Delta {{H}_{f}}(H)=218kJ/mol\]
D) \[H-H\]
Correct Answer: B
Solution :
Let the concentration of potassium acetate is x. From Hendersons equation, \[pH=p{{K}_{a}}+\log \frac{[salt]}{[acid]}\] \[4.8=-\log (1.8\times {{10}^{-5}})+\log \frac{x\times 50}{20\times 0.1M}\] \[4.8=4.74+\log 25x\] or \[\log 25x=0.06\] \[25x=1.148\] \[\therefore \] \[x=0.045M\]You need to login to perform this action.
You will be redirected in
3 sec