A) 2
B) \[\frac{1}{2}\]
C) 4
D) 16
Correct Answer: D
Solution :
Fringe width \[\beta =\frac{\lambda D}{d}\] Let the amplitude of that place where constructive inference takes place is a. The position of fringe at \[{{p}_{2}}\] is \[x=\frac{n\lambda D}{d}\] Given, \[\beta =\left( \frac{\beta }{4} \right)\] \[\therefore \] \[\frac{\lambda D}{4d}=\frac{n\lambda D}{d}\] or \[n=\frac{1}{4}\] \[\therefore \] \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{{{a}^{2}}}{{{\left( \frac{a}{4} \right)}^{2}}}\] or \[{{I}_{1}}:{{I}_{2}}=16:1\]You need to login to perform this action.
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