A) 0.75
B) 0.61
C) 0.51
D) 0.30
Correct Answer: C
Solution :
Alter impact the bullet and block move together and comes to rest after \[m=0.2\text{ }kg\] covering a distance of \[40\text{ }m\]. By conservation of momentum \[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}={{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}\] or \[0.02\times 250+0.23\times 0=0.02v+0.23v\] \[5+0=v(0.25)\] \[\frac{500}{25}=v=20m{{s}^{-1}}\] Now, by conservation of energy \[\frac{1}{2}M{{v}^{2}}=\mu R.d\] or \[\frac{1}{2}\times 0.25\times 400=\mu \times 0.25\times 9.8\times 40\] \[\Rightarrow \] \[\mu =\frac{200}{9.8\times 40}=0.51\]You need to login to perform this action.
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