A) \[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\]
B) \[{{H}_{3}}C-C{{H}_{2}}-C\equiv CH\]
C) \[{{H}_{2}}C=CH-C\equiv CH\]
D) \[HC\equiv C-C{{H}_{2}}-C\equiv CH\]
Correct Answer: C
Solution :
Given: \[p\pi .d\pi \] ie, \[Xe{{O}_{3}}\] \[Xe{{O}_{4}}\] or \[3:5\] \[\Delta {{H}_{f}}(H)=218kJ/mol\] \[H-H\] Thus, \[52.15\]energy is absorbed for breaking one mole of \[911\] bonds. Hence, \[104\] bond energy is 104.3 kcal/mol.You need to login to perform this action.
You will be redirected in
3 sec