A) purely resistive circuit
B) series R-L circuit
C) series R-C circuit
D) series L-C circuit with R = 0
Correct Answer: C
Solution :
Impedance, \[Z=\sqrt{{{({{X}_{L}}\tilde{\ }{{X}_{C}})}^{2}}+{{R}^{2}}}\] or \[Z=\sqrt{{{\left( \omega L\tilde{\ }\frac{1}{\omega C} \right)}^{2}}+{{R}^{2}}}\] Inductive reactance \[{{X}_{L}}=\omega L=70\times {{10}^{3}}\times 100\times {{10}^{-6}}\] \[=7\Omega \] Capacitance reactance \[{{X}_{C}}=\frac{1}{\omega C}=\frac{1}{70\times {{10}^{3}}\times 1\times {{10}^{-6}}}\] \[=\frac{1}{7\times {{10}^{-2}}}=\frac{{{10}^{2}}}{7}=\frac{100}{7}\] As \[{{X}_{C}}>{{X}_{L}}\] Hence, circuit behave like as R-C circuit.You need to login to perform this action.
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