A) \[{{H}_{3}}C-C{{H}_{2}}-C\equiv CH\]
B) \[{{H}_{2}}C=CH-C\equiv CH\]
C) \[HC\equiv C-C{{H}_{2}}-C\equiv CH\]
D) \[NaOH\]
Correct Answer: C
Solution :
For a first order reaction, \[t=\frac{2.303}{\lambda }{{\log }_{10}}\frac{a}{a-x}\] Let initial amount of reactant is 100. \[\frac{{{t}_{1}}}{{{t}_{2}}}=\frac{\log \frac{100}{100-75}}{\log \frac{100}{100-25}}\] [\[\because \]\[\lambda \]remains constant] \[=\frac{\log \frac{100}{25}}{\log \frac{100}{75}}=\frac{\log 4}{\log 4/3}\] \[=\frac{log4}{\log 4-\log 3}\] \[=\frac{0.6020}{0.1249}=4.81\]You need to login to perform this action.
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