A) \[N{{H}_{3}}\]
B) \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\]
C) \[{{({{C}_{6}}{{H}_{5}})}_{3}}N\]
D) \[{{({{C}_{6}}{{H}_{5}})}_{2}}NH\]
Correct Answer: C
Solution :
Presence of electron withdrawing group like Ph group decreases the electron density of nitrogen and hence, the lone pair of nitrogen are not available for donation. Thus, \[({{C}_{6}}{{H}_{5}})\] is least basic because of the presence of three electron withdrawing \[Ph({{C}_{6}}{{H}_{5}})\] groups.
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