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VIT Engineering VIT Engineering Solved Paper-2010

  • question_answer
    The radius of \[N{{a}^{+}}\] is 95 pm and that of \[C{{l}^{-}}\] ion is 181 pm. Hence, the coordination number of \[N{{a}^{+}}\] will be

    A)  4                

    B)  6

    C)  8               

    D)  unpredictable

    Correct Answer: B

    Solution :

     \[\frac{radius\,\,of\,\,cartion,\,\,{{r}^{+}}}{radius\,\,of\,anion,\,{{r}^{-}}}=\frac{95}{181}=0.525\] This value lies in between \[0.414-0.732\], thus, the coordination number of \[N{{a}^{+}}\] ion will be 6.


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