A) 10 mA
B) 40 mA
C) 80 mA
D) 160 mA
Correct Answer: C
Solution :
In space charge limited region, the plate current is given by Childs law \[{{i}_{p}}=KV_{p}^{3/2}\] Thus, \[\frac{{{i}_{p2}}}{{{i}_{p1}}}={{\left( \frac{{{V}_{p2}}}{{{V}_{p1}}} \right)}^{3/2}}={{\left( \frac{600}{150} \right)}^{3/2}}\] \[={{(4)}^{3/2}}=8\] or \[{{i}_{p2}}={{i}_{p1}}\times 8=10mA=80mA\]You need to login to perform this action.
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