A) 5/3
B) 4/3
C) \[\sqrt{3}\]
D) 5/4
Correct Answer: A
Solution :
Here, \[5=(1.5-1)\left( \frac{2}{R} \right)\] If a lens (made of glass) of refractive index \[{{\mu }_{g}}\] is immersed in a liquid of refractive index a \[{{\mu }_{l}},\]then its focal length in liquid \[{{f}_{1}}\] is given by \[\frac{1}{{{f}_{1}}}={{(}_{l}}{{\mu }_{g}}-1)\left[ \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right]\] \[-1=\left( \frac{1.5}{n}-1 \right)\left( \frac{2}{R} \right)\] Dividing, \[-5=\frac{0.5n}{1.5-n}\] or \[-7.5+5n=0.5n\]c or \[-7.5=-4.5n\] or \[n=\frac{75}{45}=\frac{5}{3}\]You need to login to perform this action.
You will be redirected in
3 sec