A) Geometrical
B) Optical
C) Linkage
D) lonisation
Correct Answer: D
Solution :
\[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]N{{O}_{2}}\] and \[[Co{{(N{{H}_{3}})}_{4}}ClN{{O}_{2}}]Cl\]give different ions on ionisation as \[[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]N{{O}_{2}}\xrightarrow{{}}{{[Co{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]}^{+}}\] \[+NO_{2}^{-}\] \[[Co{{(N{{H}_{3}})}_{4}}ClN{{O}_{2}}]Cl\xrightarrow{{}}{{[Co{{(N{{H}_{3}})}_{4}}ClN{{O}_{2}}]}^{+}}\] \[+C{{l}^{-}}\] Thus, they show ionisation isomerism.
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