A) \[2{{X}^{2}}+3{{Y}^{2}}=6\]
B) \[2{{X}^{2}}+{{Y}^{2}}=6\]
C) \[{{X}^{2}}+2{{Y}^{2}}=6\]
D) None of the above
Correct Answer: B
Solution :
Substituting \[x=X+1\]and \[y=Y-2\]in given equation, we get \[2{{(X+1)}^{2}}+{{(Y-2)}^{2}}-4\,(X+1)+4\,(Y-2)=0\] \[\Rightarrow \]\[2{{X}^{2}}+{{Y}^{2}}=6\]
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