A) 12 sq units
B) 13 sq units
C) \[13\frac{1}{2}\] sq units
D) 14 sq units
Correct Answer: D
Solution :
Required area\[=\int_{3}^{5}{(3x-5)dx}\] \[=\left[ \frac{3{{x}^{2}}}{2}-5x \right]_{3}^{5}\] \[=\left[ \frac{75}{2}-25 \right]-\left[ \frac{27}{2}-15 \right]\] \[=\frac{48}{2}-10=14\,\text{sq}\,\text{units}\]
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