A) 24.3 mg
B) 16.6 mg
C) 17.6 mg
D) 21.3 mg
Correct Answer: C
Solution :
\[P=100W\] and \[~V=125V\] \[P=VI\] \[\Rightarrow \] \[I=\frac{P}{V}=\frac{100}{125}A\] Mass of chlorine liberated = Zit \[=0.367\times {{10}^{-6}}\times \frac{100}{125}\times 60\] \[=0.0176\times {{10}^{-3}}kg\] \[=17.6mg\]You need to login to perform this action.
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