A) \[0.1\text{ }V\]
B) \[8\text{ }V\]
C) \[2\text{ }V\]
D) \[0.5\text{ }V\]
Correct Answer: A
Solution :
Potential difference between two points in an electric field is \[{{V}_{A}}-{{V}_{B}}=\frac{W}{{{q}_{0}}}\] where W is work done by moving charge \[{{q}_{0}}\] from point A to B Here, \[W=2J,\,{{q}_{0}}=20C\] \[{{V}_{A}}-{{V}_{B}}=\frac{2}{20}\] \[=0.1volt\]You need to login to perform this action.
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