A) 0.0005 V/cm
B) 0.05 V/cm
C) 0.02V/cm
D) 0.2 V/cm
Correct Answer: A
Solution :
Potential gradient \[=\frac{e}{(R+{{R}_{h}}+r)}.\frac{R}{L}\] \[=\frac{2}{(15+5+0)}\times \frac{5}{1}\] \[=0.5V/m\] \[=0.005V/cm\]You need to login to perform this action.
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