A) \[1842.4\text{ }R\]
B) \[460.6\text{ }R\]
C) \[230.3\text{ }R\]
D) \[921.2\text{ }R\]
Correct Answer: D
Solution :
At \[{{T}_{1}}=200K,\] if \[{{k}_{1}}=k\] then at \[{{T}_{2}}=400K,\,\,{{k}_{2}}=10k\] \[\log \frac{10k}{k}=\frac{{{E}_{a}}}{2.303R}\left( \frac{400-200}{400\times 200} \right)\] \[{{E}_{a=}}921.2R\]You need to login to perform this action.
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