A) 20
B) 40
C) 60
D) 80
Correct Answer: C
Solution :
Let z = x + iy, then \[\log \frac{0.1}{0.8}=\left( n-1 \right)\log \frac{50}{400}\] and \[\log \frac{1}{8}=\left( n-1 \right)\log \frac{1}{8}\] Then, the area of the triangle formed by these lines is \[0.90=\left( n-1 \right)0.90\] Applying \[\Rightarrow \] \[2Na+2{{H}_{2}}O\to 2NaOH+{{H}_{2}}\uparrow \] \[2NaOH+C{{O}_{2}}\to N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O\] \[N{{a}_{2}}C{{O}_{3}}+2HCl\to 2NaCl+{{H}_{2}}O+C{{O}_{2}}\] (given) \[{{p}^{5+}}.\] \[8Al\to 8A{{l}^{3+}}+24{{e}^{-}}\] \[9F{{e}^{8/3+}}+24{{e}^{-}}\to 9Fe\]
You need to login to perform this action.
You will be redirected in
3 sec
