VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
    If the electron in the hydrogen atom jumps from third orbit to second orbit, the wavelength of the emitted radiation in term of Rydberg constant is

    A)  \[\frac{6}{5R}\] 

    B)                        \[\frac{36}{5R}\]

    C)  \[\frac{64}{7R}\]                                             

    D)  None of these

    Correct Answer: B

    Solution :

    \[n{{'}_{He}}:n{{'}_{C{{H}_{4}}}}:n{{'}_{S{{O}_{2}}}}=4:4:3.\]                   \[mvr=\frac{nh}{2\pi }=\frac{3\times h}{2\pi }=\frac{1.5h}{\pi }\]             \[=3h\left[ \because h=\frac{h}{2\pi } \right]\]                    \[\underset{276g}{\mathop{A{{g}_{2}}C{{O}_{3}}}}\,\xrightarrow{\Delta }\underset{216g}{\mathop{2Ag}}\,+C{{O}_{2}}+\frac{1}{2}{{O}_{2}}\]                 \[A{{g}_{2}}C{{O}_{3}}\]


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