VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
    The daniel cell is balanced on 125 cm length of a potentiometer. Now, the cell is ?short circuited by a resistance of 2\[\Omega \], and the balance is obtained at 100 cm. The internal resistance of the daniel cell is

    A) \[\frac{4}{3}\Omega \]                 

    B) 1.50 \[\Omega \]

    C) 1.25\[\Omega \]                              

    D) 0.5 \[\Omega \]

    Correct Answer: D

    Solution :

    \[=\frac{{{10}^{5}}}{2\pi }Hz\]                 \[E=\frac{12375}{5000}\]                  \[=2.475eV=4\times {{10}^{-19}}J\]                  \[{{\text{l}}_{\text{eye}}}\text{=}\left( \text{photon flux} \right)\text{ }\!\!\times\!\!\text{ energy of a photon}\]                   \[{{\text{l}}_{\text{eye}}}\text{=}\left( 5\times {{10}^{4}} \right)\times 4\times {{10}^{-19}}\]


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