A) \[\frac{{{10}^{5}}}{2\pi }Hz\]
B) \[\frac{{{10}^{6}}}{2\pi }Hz\]
C) \[2\pi \times {{10}^{5}}Hz\]
D) \[2\pi \times {{10}^{6}}Hz\]
Correct Answer: A
Solution :
Impedance of L-C-R circuit will be minimum for a resonant frequency so, \[=2.81\times {{10}^{-23}}c{{m}^{3}}\] \[\underset{\left( nolp \right)}{\mathop{NH_{4}^{+}}}\,>\underset{\left( 1lp \right)}{\mathop{N{{H}_{3}}}}\,>\underset{\left( 2lp \right)}{\mathop{NH_{2}^{-}}}\,\] \[{{k}_{f}}=1.1\times {{10}^{-2}},{{k}_{b}}=1.5\times {{10}^{-3}}\]
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